For a series LCR circuit, the power loss at resonance is :

For a series LCR circuit, the power loss at resonance is :

A
$\frac{V^{2}}{(ωL - \frac{1}{ωC})}$
B
$I^{2} ωL$
C
I² R
D
$\frac{V^{2}}{ωC}$

Solution:

In ac circuit, power loss = VI cos $ϕ$

= VI = I²R ( $∵$ $ϕ$ = 0 at resonance)

Related content

Appreciation Words

Wave Optics Mind Map

Alternating Current Mind Map for Class 12, JEE & NEET

Paramedical Courses After Class 10

Top Courses After 12th Science with PCM, PCB and PCMB

Subject Change Application in School and College

CBSE Class 10 Result 2024: Is the Release Date Early? Check Expected Schedule

Mizoram NEET Merit List 2023

Government Jobs After 12th Arts Stream

Chhattisgarh NEET UG Merit List 2023