Let v1 be the frequency of series limit of Lyman series, v2 the frequency of the first line of Lyman series, and v3 the frequency of series limit of Balmer series. Then which of the following is correct?

A
$v_{1} - v_{2} = v_{3}$
B
$v_{2} - v_{1} = v_{3}$
C
$v_{3} = \frac{1}{2} (v_{1} + v_{2})$
D
$v_{2} + v_{1} = v_{3}$

Solution:

Series limit means the shortest possible wavelength (maximum photon energy) and first line means the largest possible wavelength (minimum photon energy) in the series.

$v = C [\frac{1}{n^{2}} - \frac{1}{m^{2}}]$ (where C is a constant)

For series limit of Lyman series:
$n = 1, m = \infty \Rightarrow v_{1} = C$
For first line of Lyman series:
$n = 1, m = 2 \Rightarrow v_{2} = 3 C / 4$
For series limit of Balmer series:
$n = 2, m = \infty \Rightarrow v_{3} = C / 4$
Only option (a) is correct.

Let $v_{1}$ be the frequency of series limit of Lyman series, $v_{2}$ the frequency of the first line of Lyman series, and $v_{3}$ the frequency of series limit of Balmer series. Then which of the following is correct?

Solution:

Related content

Company

Support

Courses

More

JEE

NEET

CUET

CBSE

Popular books

NCERT solutions

NCERT exemplar

State Board

Subject

follow us