The angle between the two vectors – 2i^ +3j^ +k^ and i^+2j^-4k^ is:

The angle between the two vectors $- 2 \hat{i} + 3 \hat{j} + \hat{k}$ and $\hat{i} + 2 \hat{j} - 4 \hat{k}$ is:

A
0°
B
90°
C
180°
D
none of these

Solution:

${θ=cos}^{- 1} (\frac{\vec{A} . \vec{B}}{AB}); Here \vec{A} . \vec{B} = 0, so θ = 90 °$

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