The electric field of plane electromagnetic wave of amplitude 2V/m varies with time, propagating along z-axis. The average energy density of magnetic field in J/m3 is equal to x×10−12 J/m3. Then ‘x’ value is equal to (∈0=8.854×10−12 F/m)

Solution:

1. Given Electric Field $E = 2 V / m$
$ε_{0} = 8.854 \times 10^{- 12} F / m$
Equating the average energy density of electric and magnetic field
$\begin{array}{l} <u_{B}> = <u_{E}> \\ = \frac{1}{4} ε_{0} E_{0}^{2} = \frac{1}{4} \times 8.854 \times 10^{- 12} \times (2)^{2} \\ = 8.85 \times 10^{- 12} J / m^{2} \end{array}$

Therefore, the correct answer is 8.85

The electric field of plane electromagnetic wave of amplitude 2V/m varies with time, propagating along z-axis. The average energy density of magnetic field $(in J / m^{3})$ is equal to $x \times 10^{- 12} J / m^{3}$ . Then ‘x’ value is equal to ( $\in_{0} = 8.854 \times 10^{- 12} F / m$ )

Solution:

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