Solution:
1 electron has a charge of 1.6 x 10-19 C.
1010 electrons would have a charge of
q = ne = 1.6 x 10-19 x 1010
= 1.6 x 10-9 C
Thus, in Is charge accumulated = 1.6 x 10-9 C
So, time taken to accumulate 1 C
= 6.25 x 108 s = 173611 h
= 7233 days 20 yr
