An electron moving with the speed 5 x 106 ms-1 is shooted parallel to the electric field of intensity 1 X 103 N/C. Field is responsible for the retardation of motion of electron. Now, evaluate the distance travelled by the electron before coming to rest for an instant. (Mass of electron = 9 X 10-31 kg and charge = 1.6 X 10-19 C)

An electron moving with the speed 5 x 10⁶ ms^-1 is shooted parallel to the electric field of intensity 1 X 10³ N/C. Field is responsible for the retardation of motion of electron. Now, evaluate the distance travelled by the electron before coming to rest for an instant. (Mass of electron = 9 X 10^-31kg and charge = 1.6 X 10^-19 C)

A
7 m
B
0.7 mm
C
7 cm
D
0.7 cm

Solution:

Electric force, $q E = m a \Rightarrow a = \frac{q E}{m}$

$∴ a = \frac{1.6 \times 10^{- 19} \times 1 \times 10^{3}}{9 \times 10^{- 31}} = \frac{1.6}{9} \times 10^{15}$

$∵ u = 5 \times 10^{6} {ms}^{- 1} and v = 0$

$∴ From v^{2} = u^{2} - 2 a s \Rightarrow s = \frac{u^{2}}{2 a}$

$∴ Distance, s = \frac{{(5 \times 10^{6})}^{2} \times 9}{2 \times 1.6 \times 10^{15}} = 7 cm (approx.)$

Related content

Top 55 Quotes on Virat Kohli by Fans That Show Pure Admiration

NEET 2025 Cut Off is Expected, Check Category Wise Qualifying Marks for MBBS and BDS

National Anti-Terrorism Day 2025, Theme, History and Observance in India

World Telecommunication and Information Society Day 2025 (May 17th)

CBSE Worksheets for Class 12 – All Subjects Free PDF Download with Solutions

CBSE Class 11 English Worksheet Chapter 2 – A Photograph

CBSE Class 7 Perimeter And Area Worksheets With Answers

CBSE Class 11 English Worksheet Chapter 1 The Portrait of a Lady

Wastewater Story Class 7 MCQ With Answers

MCQ Questions for Class 7 Maths Chapter 5 Lines and Angles