The cricket ball of mass 70 g moving with velocity of 0.5 m/s is stopped by a player in 0.5 second. What will be the force applied by the player to stop the ball?

The cricket ball of mass

70 g

moving with velocity of

0.5 m / s

is stopped by a player in

0.5 second

. The force acting on the cricket ball is

0.07 N

.
Given data in the problem,
Velocity of the cricket ball,

u = 0.5 m / s

Time,

t = 0.5 s

Mass of the cricket ball,

m = 70 g

And

70 g

can be written as

0.07 kg

Assuming

v = 0

By using the first equation of motion

v = u + at

Where,

v = final velocity

u = initial velocity

a = acceleration

t = time

\Rightarrow 0 = 0.5 + a \times 0.5

\Rightarrow a = - \frac{0.5}{0.5}

\Rightarrow a = - 1 m s^{- 2}

(Negative sign shows that the acceleration is in negative or say retardation)
so, the force exerted in the cricket ball is given by

Force = mass \times acceleration

\Rightarrow F = 0.07 \times (1)

\Rightarrow F = 0.07

The force acting on the cricket ball is

0.07 N

The cricket ball of mass $70 g$ moving with velocity of $0.5 m / s$ is stopped by a player in $0.5 second$ . What will be the force applied by the player to stop the ball?