A submarine emits a SONAR pulse, which returns from an underwater cliff in 1.02 s. If the speed of sound in seawater is 1531 m/s then the cliff is [[1]] m far away from the submarine.

A submarine emits a SONAR pulse, which returns from an underwater cliff in

1.02 s

. If the speed of sound in seawater is

1531 m / s

then the cliff is

780.81 m

far away from the submarine.
Given,
the time between transmission and reception of sonar pulse,

t = 1.02 s

Speed of sound in seawater,

v = 1531 m / s

As, the distance travelled by the sonar pulse

= 2 \times distance between the submarine and the cliff (d)

= 2 d

So,

2 d = speed of sound \times time

= 1531 \times 1.02

= 1561.62

\Rightarrow d = \frac{1561.62}{2}

= 780.81 m

Hence, the answer of the given question is

780.81 metres

A submarine emits a SONAR pulse, which returns from an underwater cliff in $1.02 s$ . If the speed of sound in seawater is $1531 m / s$ then the cliff is [[1]] $m$ far away from the submarine.