A current of 1 A is drawn by a filament of an electric bulb. The number of electrons passing through a cross-section of the filament in 16 seconds would be

When a current of

1 A

is drawn by a filament of an electric bulb, the number of electrons passing through a cross-section of the filament in

16 s

would be roughly

10^{20}

.
It is given that the current

(I)

drawn by the filament is

1 A

.
The formulas of charge are given by,

Q = ne

and

Q = It

where

Q

n

e

I

and

t

are the charge, number of electrons, charge of electron, current and time respectively.
Therefore, from the formulas it can be said that

ne = It

On substituting the given values, we get

n = \frac{It}{e} = \frac{1 \times 16}{1.6 \times 10^{- 19}}

\Rightarrow n = 10^{20}

electrons
Hence, the number of electrons passing through the cross-section of the filament in

16 s

when

1 A

of current is passing through the wire is

10^{20}

electrons.
Also Check:

A current of $1 A$ is drawn by a filament of an electric bulb. The number of electrons passing through a cross-section of the filament in $16 seconds$ would be