Two lamps, one rated 100 W, 220 V, and the other 60 W, 220 V, are connected in parallel to electric mains supply, the current drawn by the two bulbs is [[1]] A.

When two lamps, one rated

100 W

220 V

, and the other

60 W

220 V

, are connected in parallel to electric mains supply, the current drawn by the two bulbs is

0.72 A

.
It is given that two bulbs of ratings

100 W

220 V

and

60 W

220 V

are connected in parallel combination with the mains.
Let the bulb with Power

(P) = 100 W

and potential difference

V = 220 V

be Bulb

1

.
Let the bulb with Power (

P) = 60 W

and potential difference

V = 220 V

be Bulb

2

.
It is known that the power of the component is given by the relation

P = VI

It can be written as

I = \frac{P}{V}

Where

I, P

and

V

are the current, power and potential difference respectively.
Therefore, the current drawn by bulb

1

\Rightarrow I_{1} = \frac{100}{220}

\Rightarrow I_{1} = \frac{5}{11} A

Similarly, the current drawn by bulb

2

I_{2} = \frac{60}{220}

\Rightarrow I_{2} = \frac{3}{11} A

Therefore, the total current drawn by the two bulbs is

I_{1} = I_{1} + I_{2}

\Rightarrow I = \frac{5}{11} + \frac{3}{11}

\Rightarrow I = \frac{8}{11}

\Rightarrow I = 0.72 A

Hence, the current drawn by two bulbs is

0.72 A

Two lamps, one rated $100 W$ , $220 V$ , and the other $60 W$ , $220 V$ , are connected in parallel to electric mains supply, the current drawn by the two bulbs is [[1]] $A$ .