ChemistryFind the number of inner – orbital octahedral complexes (d2sp3hybridization) of the following.[Co(H2O)6]3+,[Fe(NH3)6]2+, [CoF6]3-, [NiF6]2-,[Pt(NH3)4]Cl2, [Cr(H2O)6]3+, [Mn(CN)6]4-,[Fe(CN)6]3-,Co(NH3)62+

Find the number of inner - orbital octahedral complexes (d2sp3hybridization) of the following.

[Co(H2O)6]3+,[Fe(NH3)6]2+, [CoF6]3-, [NiF6]2-,[Pt(NH3)4]Cl2, [Cr(H2O)6]3+, [Mn(CN)6]4-,[Fe(CN)6]3-,Co(NH3)62+

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    Solution:

    Water is a moderately weak ligand and in case of Co3+, water acts as strong ligand. So, pairing of 3d-electrons takes place and Co(H2O)63+complex becomes an inner-orbital complex.

    In NiF62-, Ni is in +4 oxidation state. Although Fluoride ion is a weak ligand but due to high oxidation state of Ni, pairing of electrons takes place. Therefore, it is an inner orbital complex.

    In PtNH34Cl2, Pt is present in +2 oxidation state. Due to presence of NH3, pairing of electrons takes place and becomes an inner orbital complex.

    Water is a moderately weak ligand and in case of Cr(H2O)63+, water acts as strong ligand. So, pairing of 3d-electrons takes place and complex becomes an inner-orbital complex.

    MnCN64-, FeCN63-, CoNH362+ are also inner-orbital complexes because of the presence of strong ligands.

    Complex that are inner orbital complexes:

    [Co(H2O)6]3+ , [NiF6]2- , [Pt(NH3)4]Cl2 ,[Cr(H2O)6]3+ , [Mn(CN)6]4- ,  [Fe(CN)6]3- , [Co(NH3)6]2+

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