The mode of the following data is 36 Find the missing frequency x in it.

The data from which value of x is to be calculated is given as:

Formula to find mode is

M = l + f 1 − f 0 2 f 1 − f 0 − f 2 × h

.
In the formula, l will be the lower limit of modal class. h will be the size of class intervals.

f_{0}

will be frequency of modal class,

f_{1}

will be frequency of preceding modal class,

f_{2}

will be the frequency of succeeding modal class.
And from above class interval which has highest frequency is

30 - 40

.
Here,

h = 10, l = 30, f_{0} = x, f_{1} = 16 and f_{2} = 16

\Rightarrow 36 = 30 + (\frac{16 - x}{2 (16) - x - 12}) \times 10

\Rightarrow 120 x - 6 x = 160 - 10 x

\Rightarrow 4 x = 40

\Rightarrow x = 10

Considering the calculation done above, the value of

x

is 10.
Therefore, option 3 is correct.

The mode of the following data is 36 Find the missing frequency $x$ in it.