MathematicsA student walks from his house at least 4 km per hour and reaches his school late by 5 minutes. If his speed had been increased by 5 km per hour then he would have reached 10 minutes early. The distance of the school from his house is

A student walks from his house at least 4 km per hour and reaches his school late by 5 minutes. If his speed had been increased by 5 km per hour then he would have reached 10 minutes early. The distance of the school from his house is


  1. A
    35km
  2. B
    5km
  3. C
    6km
  4. D
    4km  

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    Solution:

    Given, a student walks from his house at least 4 km per hour and reaches his school late by 5 minutes.
    If his speed had been increased by 5 km per hour then he would have reached 10 minutes early.
    Let the actual time be t and distance be x km.
    Now according to first condition, we have,
    ⇒ x4=t+560 And according to second condition, we have,
    ⇒ x5=t-1060 ⇒ 60x=4t+20 ⇒ 60x=5t-50 Subtracting first equation from second equation, we have,
    ⇒ 0=t-70 ∴t=70 s
    Putting the value of t in first equation, we get,
    ⇒ x=5 km Hence, the correct option is 2.
     
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