Solution:
Given that, , HCF(x, y)=3.LCM the least common multiple of two integers a and b, usually denoted by LCM(a, b), is the smallest positive integer that is divisible by both a and b.
Now, LCM×HCF = Product of two numbers LCM(x,y)=
Thus, if and HCF(x,y) , then LCM(x,y).
Therefore, option (1) is correct.
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