BotanyFor A + B ⇌C + D, if initially the concentrations of A and B are equal but at equilibrium, concentration of D is twice that of A. The equilibrium constant of the reaction is

For A + B $⇌$ C + D, if initially the concentrations of A and B are equal but at equilibrium, concentration of D is twice that of A. The equilibrium constant of the reaction is

A
$\frac{4}{9}$
B
$\frac{9}{4}$
C
$\frac{1}{9}$
D
4

Solution:

$A + B ⇌ C + D$

1 1 0 0 (Given conditions)

1-x 1-x x x (Equilibrium conditions)

Given ,

$[D] = 2 [A] x = 2 (1 - x) x = 2 - 2 x x = \frac{2}{3}$

$[A] = 1 - \frac{2}{3} = \frac{1}{3} = [B] : [C] = [D] = x = \frac{2}{3}$

$k_{C} = \frac{[C] [D]}{[A] [B]} = \frac{\frac{2}{3} \times \frac{2}{3}}{\frac{1}{3} \times \frac{1}{3}} = 4$

For A + B $⇌$ C + D, if initially the concentrations of A and B are equal but at equilibrium, concentration of D is twice that of A. The equilibrium constant of the reaction is

Solution:

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