Solution:
Let molar mass of the compound be x g. Then mass of sulphur present = 0.08 x g.
1 molecule of the compound contain at least 1 atom of sulphur, so 1 mol of the compound must contain at least 1 mol of sulphur atoms, i.e., 32g.
The least molar mass of the compound is 400g. Since the molar mass (in g) is numerically equal to the molecular mass, the least molecular mass of the compound = 400.
