Solution:
Molecular weight of CaCO3 = 100 gm
100 gm of sample contains = 40 gm of Ca
4 gm of sample contains = ?
= gm
A sample of calcium carbonate (CaCO3) has the following percentage composition : Ca = 40%, C : 12%, O = 48%. If the law of constant proportions is true, then the weight of calcium in 4 g of a sample of calcium carbonate obtained from another source will be :
A sample of calcium carbonate (CaCO3) has the following percentage composition : Ca = 40%, C : 12%, O = 48%. If the law of constant proportions is true, then the weight of calcium in 4 g of a sample of calcium carbonate obtained from another source will be :
