ChemistryConsider the oxidation of iodide ion by hydrogen peroxide in an acidic solution.H2O2(aq)+3I−(aq)+2H+(aq)→I3−(aq)+2H2O(l)The rate of formation of the brown-coloured tri-iodide ion ΔI3−/Δt  can bedetermined by measuring the rate of appearance of the colour. Following are initialrate data at 25°C.ExperimentInitial H2O2Initial I−Initial rate of formation of I3−(M/S)10.1000.1001.15×10−420.1000.2002.30×10−430.2000.1002.30×10−440.2000.2004.60×10−4

Consider the oxidation of iodide ion by hydrogen peroxide in an acidic solution.
H2O2(aq)+3I(aq)+2H+(aq)I3(aq)+2H2O(l)
The rate of formation of the brown-coloured tri-iodide ion ΔI3/Δt  can be
determined by measuring the rate of appearance of the colour. Following are initial
rate data at 25°C.

ExperimentInitial H2O2Initial IInitial rate of formation of I3(M/S)
10.1000.1001.15×104
20.1000.2002.30×104
30.2000.1002.30×104
40.2000.2004.60×104

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    Solution:

    The rate of formation of the brown-coloured tri-iodide ion ΔI3−/Δt\Delta \text{I}_3^-/\Delta tΔI3−/Δt can be determined by measuring the rate of appearance of the colour. Given the initial rate data at 25°C, we can analyze how the concentration of H2O2\text{H}_2\text{O}_2H2O2 and I−\text{I}^-I− affect the rate.

    From the data:

    1. Experiment 1: [H2O2]=0.100[ \text{H}_2\text{O}_2 ] = 0.100[H2O2]=0.100 M, [I−]=0.100[ \text{I}^- ] = 0.100[I−]=0.100 M, Initial rate = 1.15×10−41.15 \times 10^{-4}1.15×10−4 M/s
    2. Experiment 2: [H2O2]=0.100[ \text{H}_2\text{O}_2 ] = 0.100[H2O2]=0.100 M, [I−]=0.200[ \text{I}^- ] = 0.200[I−]=0.200 M, Initial rate = 2.30×10−42.30 \times 10^{-4}2.30×10−4 M/s
    3. Experiment 3: [H2O2]=0.200[ \text{H}_2\text{O}_2 ] = 0.200[H2O2]=0.200 M, [I−]=0.100[ \text{I}^- ] = 0.100[I−]=0.100 M, Initial rate = 2.30×10−42.30 \times 10^{-4}2.30×10−4 M/s
    4. Experiment 4: [H2O2]=0.200[ \text{H}_2\text{O}_2 ] = 0.200[H2O2]=0.200 M, [I−]=0.200[ \text{I}^- ] = 0.200[I−]=0.200 M, Initial rate = 4.60×10−44.60 \times 10^{-4}4.60×10−4 M/s

    From these experiments, it's observed that doubling the concentration of either H2O2\text{H}_2\text{O}_2H2O2 or I−\text{I}^-I− doubles the initial rate of formation of I3−\text{I}_3^-I3−. Therefore, the reaction is first order with respect to both H2O2\text{H}_2\text{O}_2H2O2 and I−\text{I}^-I−.

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