Solution:
No. of moles of Zn required = 1
No. of moles of Fe required = 1
No. of moles of S required = 2
Given,
moles of Zn = 2
moles of Fe = 3
moles of S = 5
Thus, Zn is the limiting reagent and according to stoichiometry, 2 moles of the compound will be formed.
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