In the following reaction (unbalanced), equivalent weight of As2S3 is related to molecular weight M byAs2S3 + H+ + NO3- → NO + H2O + AsO43- + SO42-

In the following reaction (unbalanced), equivalent weight of ${As}_{2} S_{3}$ is related to molecular weight M by
${As}_{2} S_{3} + H^{+} + {NO}_{3}^{-} \overset{}{\to} NO + H_{2} O + {AsO}_{4}^{3 -} + {SO}_{4}^{2 -}$

A
$\frac{M}{2}$
B
$\frac{M}{4}$
C
$\frac{M}{28}$
D
$\frac{M}{24}$

Solution:

${\overset{+ 3}{As}}_{2} {\overset{- 2}{S}}_{3} \overset{}{\to} \overset{+ 5}{As} O_{4}^{3 -} + 3 \overset{+ 6}{S} O_{4}^{2 -}$

Change in ox. state of ‘As’ = 2(2) = 4

Change in Ox. state of ‘S’ = 3(8) = 24

Net change in Oxidation state = 28

Thus, equivalent mass of ${As}_{2} S_{3} = \frac{M}{28}$

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