Molarity of 200 ml of HCl solution which can neutralise 10.6 g. of anhydrous Na2CO3 is

Molarity of 200 ml of HCl solution which can neutralise 10.6 g. of anhydrous Na2CO3 is

  1. A

    0.1M

  2. B

    1M

  3. C

    0.6M

  4. D

    0.75M

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    Solution:

    Gram equivalent of Na2CO3 = Gram equivalent of HCl

    large frac{W}{GEW} = frac{V_aN_a}{1000}

    Wt of Na2CO3 = 10.6

    GEW of Na2CO3 = 53g

    Volume of HCl = 200ml

    large therefore frac{10.6}{53} = frac{200(M_a)1}{1000}

    Ma = 1M

    Molarity of HCl = 1M

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