Suppose, the elements X and Y combine to form two compounds XY2 and X3Y2. When 0.1 mole of XY2 weights 10 g and 0.05 mole of X3Y2 weights 9 g, the atomic weights of X and Y are

Suppose, the elements X and Y combine to form two compounds XY₂ and X₃Y₂. When 0.1 mole of XY₂ weights 10 g and 0.05 mole of X₃Y₂ weights 9 g, the atomic weights of X and Y are

A
30, 20
B
40, 30
C
60, 40
D
20, 30

Solution:

$For {XY}_{2} n = \frac{W}{M}$
$0 .1 = \frac{10}{X + 2 Y} = X + 2 Y = 100$ ---------(i)
$For X_{3} Y_{2} n = \frac{W}{M}$
$0 .05 = \frac{9}{3 X + 2 Y} = 3 X + 2 Y = 180 - - - - - - - (ii)$
From (i) and (ii)
2X = 80
X = 40 and 2Y = 100 - 40 = 60
Y = 30

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