The density of a solution containing 13% by mass of sulphuric acid is1.09 g/mL . Then, the molarity of the solution is

The density of a solution containing $13 %$ by mass of sulphuric acid is $1.09 g/mL$ . Then, the molarity of the solution is

Mass percentage of sulphuric acid ,

x = 13 %

Density, $d = 1.09 g / mL$

GMW of $H_{2} {SO}_{4} = 98$

The formula used to find molarity is

$M = \frac{10 \times d \times x}{GMW}$

$Molarity = \frac{10 \times 1.09 \times 13}{98} = 1.445 M$

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