MathematicsFind a quadratic polynomial whose zeroes are 5-3√2 and 5+3√2.

Find a quadratic polynomial whose zeroes are 5-3√2 and 5+3√2.


  1. A
    P(x)=x2−10x+7
  2. B
    P(x)=x2−10x+5
  3. C
    P(x)=x2−50x+7
  4. D
    P(x)=x2−10x-7 

    Fill Out the Form for Expert Academic Guidance!l



    +91



    Live ClassesBooksTest SeriesSelf Learning



    Verify OTP Code (required)

    I agree to the terms and conditions and privacy policy.

    Solution:

    Given that zeros of a polynomial are 5-3√2 and 5+3√2.
    Now, polynomial is given by,
    P(x)=x2-(Sum of zeroes)x+ product of zeroes……….(1)
    Sum=(5−3√2)+(5+3√2)
    ⇒Sum=10
    Product =(5−3√2)(5+3√2)
    ⇒Product=52-322      [a2-b2=a-ba+b]
    ⇒Product=25-9×2  ⇒Product=25-18 ⇒Product=7 From equation (1) we get,
    P(x)=x2−10x+7
    Thus, the quadratic equation is P(x)=x2−10x+7 .
    Therefore, option (1) is correct.
     

    Related content

    Matrices and Determinants_mathematics
    Chat on WhatsApp Call Infinity Learn