If the straight line, 2x−3y+17=0 is perpendicular to the line passing through the points (7,17) and (15,β), then β=

If the straight line, 2x3y+17=0 is perpendicular to the line passing through the points (7,17) and (15,β), then β=

  1. A

    -5

  2. B

    -35/3

  3. C

    35/3

  4. D

    5

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    Solution:

     Slope of 2x3y+17=0 is 2/3
    Slope of line joining (7,17),(15,β) is β17157=β178. 
    The lines are perpendicular 23β178=1β17=12β=5

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