If f(x)=sin⁡ex−2−1log⁡(x−1), then  limx→2 f(x)is given by

If f(x)=sinex21log(x1), then  limx2f(x)is given by

  1. A

    -2

  2. B

    -1

  3. C

    0

  4. D

    1

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    Solution:

    We have,

    limx2f(x)=limx2sinex21log(x1)limx2f(x)=limx2sinex21ex21ex21x2x2log(1+(x2))limx2f(x)=1×1×1=1

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