Solution:
Let the equation of side AB
…(i)
and, the equation of side AC is 4x + 5y - 20 = 0
…(ii)
Solving (i) and (ii), we get vertex .
Now, slope of
Slope of perpendicular
Also, BE passes through orthocentre H(l, 1)
Equation of BE is
…(iii)
Solving (i) and (iii), we get vertex .
Now, slope of
Slope of perpendicular
Equation of CF is
….(iv)
Solving (ii) and (iv), we get vertex
Equation of side BC is