An object of mass 0.2 kg executes simple harmonic motion along the x-axis with a frequency of 25/π Hz. At the position x = 0.04 m, the object has a kinetic energy of 0.5 J and potential energy of 0.4 J. The amplitude of oscillation is

A
0.05 m
B
0.06 m
C
0.01 m
D
none of these

Solution:

$E = \frac{1}{2} {mω}^{2} A^{2} = \frac{1}{2} m {(2 πf)}^{2} A^{2} A = \frac{1}{2 πf} \sqrt{\frac{2 E}{m}} Putting E = K + U, we get A = \frac{1}{2 π (25 / π)} \sqrt{\frac{2 \times (0.5 + 0.4)}{0.2}} = 0.06 m$

An object of mass 0.2 kg executes simple harmonic motion along the x-axis with a frequency of 25/π Hz. At the position x = 0.04 m, the object has a kinetic energy of 0.5 J and potential energy of 0.4 J. The amplitude of oscillation is

Solution:

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