The dimensions of the coefficient of thermal conductivity are:

A
MLT^-3 K^-1
B
MLT^-2 K^-1
C
MLT^{- 1} K^{- 1}
D
MLT^-2 K^-2

Solution:

The coefficient of thermal conductivity is defined as the rate of flow of heat energy per unit area of cross-section per unit temperature gradient. The dimensions of rate of flow of heat are $\frac{{ML}^{2} T^{- 2}}{T} = {ML}^{2} T^{- 3}$ .

dimensions of area = L²

the dimensions of temperature gradient = dimensions of temperature/dimension of length = KL^{- 1}.

Hence, the dimensions of the coefficient of thermal conductivity are $\frac{{ML}^{2} T^{- 3}}{L^{2} \times {KL}^{- 1}} = {MLT}^{- 3} K^{- 1} .$

The dimensions of the coefficient of thermal conductivity are:

Solution:

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