The potential energy of a simple harmonic oscillator when the particle is half way of its end point is :

The potential energy of a simple harmonic oscillator when the particle is half way of its end point is :

A
$\frac{2}{3} E$
B
$\frac{1}{8} E$
C
$\frac{1}{4} E$
D
$\frac{1}{2} E$

Solution:

$PE = \frac{1}{2} {kx}^{2} = \frac{1}{2} k {(\frac{a}{2})}^{2} = \frac{E}{4}$

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