The radius of curvature of the path of the charged particle in a uniform magnetic field is directly proportional to

# The radius of curvature of the path of the charged particle in a uniform magnetic field is directly proportional to

1. A

the charge on the particle

2. B

the momentum of the particle

3. C

the energy of the particle

4. D

the intensity of the field

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### Solution:

The momentum of the particle

Reason: When a charged particle enters a magnetic field (B) with the momentum $p=mv$ the then radius of path r=$\frac{mv}{Bq}⇒r\alpha mv$

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