Consider a simple pendulum having a bob attached to a string, that oscillates under the action of the force of gravity. Suppose that the period of oscillations of the simple pendulum depends on its length (l ), mass of the bob (m) and acceleration due to gravity (g). Using the method of dimensions, expression for its time period is
Two charges each equal to 2 μC are 0.5 m apart. If both of them exist inside vacuum, then the force between them is
Two charges placed in air repel each other by a force of 10−4 N. When oil is introduced between the charges, the force becomes 2.5×10−5 N. The dielectric constant of oil is
The charges on two sphere are +7μC and – 5μC respectively. They experience a force F. If each of them is given and additional charge of – 2μC, the new force of attraction will be
A particle of mass 2kg is initially at rest. A force acts on it whose magnitude changes with time. The force-time graph is shown below. The velocity of the particle at t=10 sec is
A body of mass 5kg starts from the origin with an initial velocityu→=30i^+40j^ms−1 . If a constant forceF→=−(i^+5j^)N acts on the body, the time in which the y–component of the velocity becomes zero is :
In figure, two equal positive point charges q1 = q2 = 2.0 μC interact with a third point charge Q = 4.0 μC. The magnitude, as well as direction, of the net force on Q is
Two point charges 100 μC and 5 μC are placed at points A and B respectively with AB = 40 cm. The work done by external force in displacing the charge 5 μC from B to C, where BC = 30 cm, angle ABC =π2 and 14πε0=9×109Nm2/C2 ,is
The sum of the magnitudes of two forces acting at point is 18 and the magnitude of their resultant is 12. If the resultant is at 90o with the force of smaller magnitude, what are the magnitudes of forces?
