A particle projected with velocity V0 along x-axis. The deceleration on the particle is proportional to the square of the distance from the origin i.e a=−αx2 . The distance at which the particle stops is

A particle projected with velocity V0 along x-axis. The deceleration on the particle is proportional to the square of the distance from the origin i.e a=αx2 . The distance at which the particle stops is

  1. A

    3V02α

  2. B

    (3V02α)1/3

  3. C

    3V022α

  4. D

    (3V022α)1/3

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    Solution:

    a=dvdt=dvdx.dxdt=V.dvdx=αx2

    v00Vdv=α0sx2dx

    [V022]v00=α[x33]0s

    V022=αS33

    S=[3V022α]1/3

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