Solution:
For hydrogen atom, the radius of nth orbit,
rn=52.9pm × n2
211.6pm = 52.9pm × n2
n2=4
n=2
Hence, the transition is from a higher orbit to the second orbit.
Spectral line corresponds to the Balmer series.
ChemistryThe electron in the hydrogen atom undergoes transition from higher orbitals to orbital of radius 211.6 pm. This transition is associated with
The electron in the hydrogen atom undergoes transition from higher orbitals to orbital of radius 211.6 pm. This transition is associated with
