The number of Nitrogen atoms in 681 g of C7H5 N3O6 is x.yz × 1024. The value of x.yz is_____________ NA=6.02×1023 mol-1) (Nearest Integer)

The number of Nitrogen  atoms in 681 g of C7H5 N3O6 is x.yz × 1024. The value of x.yz is_____________ NA=6.02×1023 mol-1) (Nearest Integer)

    Fill Out the Form for Expert Academic Guidance!l



    +91



    Live ClassesBooksTest SeriesSelf Learning



    Verify OTP Code (required)

    I agree to the terms and conditions and privacy policy.

    Solution:

     M.wt. of C7H5 N3O6  is 84+5+42+96=227  nC7H5N3O6=681227=3 nN=681227×3=9 mol no. of N atoms=9×6.02×1023 =5418×1021 The answer is 5418.

    Also Check:
    Chat on WhatsApp Call Infinity Learn