MathematicsA toy is in the shape of a solid cylinder surmounted by a conical cap. If the height and diameter of the cylindrical part are 21 cm and 40 cm   respectively, and height of the cone is 15 cm  , find the total surface area of the toy.

A toy is in the shape of a solid cylinder surmounted by a conical cap. If the height and diameter of the cylindrical part are 21 cm and 40 cm   respectively, and height of the cone is 15 cm  , find the total surface area of the toy.


  1. A
    6453.7c m 2  
  2. B
    5466.37 cm2
  3. C
    8463.7c m 2  
  4. D
    4463.6c m 2   

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    Solution:

    It is given that a toy is in the shape of a solid cylinder surmounted by a conical cap. The  height and diameter of the cylindrical part are 21 cm and 40 cm respectively. The height of the cone is 15 cm.
    We have to find the required slant height.
    Let R and H be the radius and height of the conical top respectively.
    Suppose the given terms r and h be the radius and height of the cylindrical part.
    As we know the Slant height of the cone,
    l=R2+H2
    l=(20)2+(15)2
    l=400+225
    l=625
    l=25 cm
    Total surface of the toy = Curved surface area of cone + Curved surface area of cylinder + Area of base.
    We know that,
    Curved surface area of cone=πRl
    Curved surface area of cylinder=2πrh
    Area of base=πr2
    Therefore,
    Total surface of the toy=πRl+2πrh+πr2
    Substituing the values,
    Total surface of the toy=π(20×25)+2π(20×21)+π(20)2
    Total surface of the toy=π(500)+2π(420)+π(400)
    Total surface of the toy=1740π
    Total surface of the toy=1740×227
    Total surface of the toy=5466.37 cm2
    The total surface area of the toy is 5466.37 cm2.
    Hence, option 2 is the correct answer.
     
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