The cricket ball of mass 70 g moving with velocity of 0.5 m/s is stopped by a player in 0.5 second. What will be the force applied by the player to stop the ball?

A
$0.07 N$
B
$0.7 N$
C
$1 N$
D
$2 N$

Solution:

The cricket ball of mass

$70 g$ moving with velocity of

$0.5 m / s$ is stopped by a player in

$0.5 second$ . The force acting on the cricket ball is

$0.07 N$ .
Given data in the problem,
Velocity of the cricket ball,

$u = 0.5 m / s$
Time,

$t = 0.5 s$
Mass of the cricket ball,

$m = 70 g$
And

$70 g$ can be written as

$0.07 kg$
Assuming

$v = 0$
By using the first equation of motion

$v = u + at$ Where,

$v = final velocity$

$u = initial velocity$

$a = acceleration$

$t = time$

$\Rightarrow 0 = 0.5 + a \times 0.5$

$\Rightarrow a = - \frac{0.5}{0.5}$

$\Rightarrow a = - 1 m s^{- 2}$ (Negative sign shows that the acceleration is in negative or say retardation)
so, the force exerted in the cricket ball is given by

$Force = mass \times acceleration$

$\Rightarrow F = 0.07 \times (1)$

$\Rightarrow F = 0.07$ The force acting on the cricket ball is

$0.07 N$ .

The cricket ball of mass $70 g$ moving with velocity of $0.5 m / s$ is stopped by a player in $0.5 second$ . What will be the force applied by the player to stop the ball?

Solution:

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