The resultant of two forces at right angle is 5 N. When the angle between them is 1200, the resultant is 13. Then, the forces are

Let, A and B be the two forces

As per question $\sqrt{A^{2} + B^{2}} = 5$

or $A^{2} + B^{2} = 25............ (i)$

and $A^{2} + B^{2} + 2 A B \cos 120^{0} = 13$

or $25 + 2 A B \times (- 1 / 2) = 13$

or $A B = 25 - 13 = 12$

or $2 A B = 24.......... (i i)$

Solving Eqs (i) and (ii), we get

$A = 3 N$

and $B = 4 N$

The resultant of two forces at right angle is 5 N. When the angle between them is $120^{0},$ the resultant is $\sqrt{13} .$ Then, the forces are