Solution:
Fnet =2|F31|cosα=2×14πε0×2×4×10−12(0.5)2×45=0.46N
In figure, two equal positive point charges q1 = q2 = 2.0 μC interact with a third point charge Q = 4.0 μC. The magnitude, as well as direction, of the net force on Q is
Fnet =2|F31|cosα=2×14πε0×2×4×10−12(0.5)2×45=0.46N