The moon is observed from two diametrically opposite points A and B on the earth. The angle θ subtended at the moon by the two directions of observation is 1∘54'. he distance of the moon from the earth is [Given diameter of earth =1.276×107 m]

Given,

$1^{\circ} 54' = 114' = (114 \times 60)'' \times (4.85 \times 10^{- 6}) r a d$

$= 3.32 \times 10^{- 2} r a d$

Since, $1'' = 4.85 \times 10^{- 6} r a d$

Also, $A B = b = 1.276 \times 10^{7} m$

$D = \frac{b}{θ}$

$D = \frac{1.276 \times 10^{7}}{3.32 \times 10^{- 2}} = 3.84 \times 10^{8} m$

The moon is observed from two diametrically opposite points A and B on the earth. The angle $θ$ subtended at the moon by the two directions of observation is $1^{\circ} 54' .$ he distance of the moon from the earth is [Given diameter of earth $= 1.276 \times 10^{7} m]$