Search for: An experiment yields 3 mutually exclusive and exhaustive events A, B and C. If P(A) = 2P(B) = 3P(C), then P(A) is equal to An experiment yields 3 mutually exclusive and exhaustive events A, B and C. If P(A) = 2P(B) = 3P(C), then P(A) is equal to A1/11B2/11C3/11D6/11 Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:Clearly,⇒P(A∪B∪C)=1⇒P(A)+P(B)+P(C)=1⇒P(A)+12P(A)+13P(A)=1⇒116P(A)=1⇒P(A)=611 Related content Amazing Facts About India Phenolphthalein Indicator Indian Talent Olympiad 2024 Chemical Formula of Blue Vitriol Vishu Festival – A Celebration of New Beginnings in Kerala Stefan’s Law Tomato Scientific Name Wein’s Displacement Law SOF Olympiad 2024-25 Arabic Month Names