How much current will an electric bulb draw from a 220 V source if the resistance of the bulb filament is 1200 Ω?

The current drawn by the electric bulb from a

220 V

source, if the resistance of the bulb filament is

1200 Ω

will be

0.18 A

.
Given that voltage

V = 220 V

and
resistance

R = 1200 Ω

Now we know that

V = IR

\Rightarrow I = \frac{V}{R}

…(1) ( in terms of current)
Where,

I =

current

V =

voltage or potential difference

R =

resistance
By putting given values in the equation (1) we get,

\Rightarrow

I = \frac{220}{1200}

\Rightarrow I = \frac{11}{60}

\Rightarrow

I = 0.18 A

How much current will an electric bulb draw from a $220 V$ source if the resistance of the bulb filament is $1200 Ω$ ?