Solution:
It is given that the radius of the quadrant is r = 7 cm and the front side of the base is been silver plated at the rate of ₹ 20 per .We have to find the total cost of silver plating.
The area of a quadrant can be expressed as, , where r is the radius of a circle.
The area of the region PBCR, is,
So, the cost of the silver plating at the rate of rupees is,
The total cost of silver plating is ₹230.
Therefore, the correct option is 4.
Related content
Matrices and Determinants_mathematics |