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NCERT Solutions For Class 10 Maths Chapter 6 Triangles Ex 6.2
NCERT chapter 6 ex 6.2 class 10 Triangles solutions are provided here, including a downloadable PDF format. These solutions, crafted by Infinity Learn subject experts, offer detailed explanations for each step. The exercise covers various concepts related to triangle similarity.
The NCERT textbook offers numerous practice questions at the end of each chapter. Solving these NCERT Solutions for Class 10 Maths and practicing regularly is sufficient for scoring well in the board exams. It’s crucial to practice each problem repeatedly until the concept is thoroughly understood.
NCERT Solutions for Class 10 Maths Chapter 6- Triangles Exercise 6.2
Question 1. In the given figure (i) and (ii), DE || BC. Find EC in (i) and AD in (ii).
Solution:
Question 2. E and F are points on the sides PQ and PR respectively of a ∆PQR. For each of the following cases, state whether EF || QR:
(i) PE = 3.9 cm, EQ = 3 cm, PF = 3.6 cm and FR = 2.4 cm
(ii) PE = 4 cm, QE = 4.5 cm, PF = 8 cm and RF = 9 cm
(iii) PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm and PF = 0.36 cm
Solution:
Question 3. In the given figure, if LM || CB and LN || CD. Prove that \(\frac { AM }{ AB } =\frac { AN }{ A{ D }^{ \bullet } } \)
Solution:
Question 4. In the given figure, DE || AC and DF || AE. Prove that \(\frac { BF }{ FE } =\frac { BE }{ E{ C }^{ \bullet } } \)
Solution:
Question 5. In the given figure, DE || OQ and DF || OR. Show that EF || QR.
Solution:
Question 6. In the given figure, A, B and C are points on OP, OQ and OR respectively such that AB || PQ and AC || PR. Show that BC || QR.
Solution:
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Question 7. Using B.P.T., prove that a line drawn through the mid-point of one side of a triangle parallel to another side bisects the third side. (Recall that your have proved it in class IX)
Solution:
Question 8. Using converse of B.P.T., prove that the line joining the mid-points of any two sides of a triangle is parallel to the third side. (Recall that your have done it in class IX)
Solution:
Question 9. ABCD is a trapezium in which AB || DC and its diagonals intersect each other at the point O. Show that \(\frac { AO }{ BO } =\frac { CO }{ D{ O }^{ \bullet } } \)
Solution:
Question 10. The diagonals of a quadrilateral ABCD intersect each other at the point O such that \(\frac { AO }{ BO } =\frac { CO }{ D{ O }^{ \bullet } } \) Show that ABCD is a trapezium.
Solution:
NCERT Solutions for Class 10 Maths Chapter 6 Triangles Ex 6.2 in Hindi Medium
Q1. आकृति 6.17 (i) और (ii) में, DE || BC में AD ज्ञात कीजिए :
हल: (i)
Δ ABC में
DE || BC दिया है |
अत: आधारभूतिक समानुपातिक प्रमेय से
Q2. किसी त्रिभुज PQR की भुजाओं PQ और PR पर क्रमशः बिन्दु E और F स्थित हैं | निम्नलिखित में से प्रत्येक स्थिति के लिए, बताइए कि क्या EF|| QR है |
(i) PE = 3.9 cm, EQ= 3cm, PF = 3.6 और FR= 2.4 cm
(ii) PE = 4 cm, QE = 4.5 cm, PF = 8 cm और RF = 9 cm
(iii) PQ = 1.28 cm, PR = 2.56 cm, 0.18 cm और PF = 0.36 cm
इसलिए, EF|| QR नहीं है |
Q7. प्रमेय 6.1 का प्रयोग करते हुए सिद्ध कीजिए कि एक त्रिभुज की एक भुजा के मध्य -बिन्दु से होकर दूसरी भुजा के समांतर खींची गई रेखा तीसरी भुजा को समद्धिभाजित करती है | (याद कीजिए की आप इसे कक्षा IX में सिद्ध कर चुके हैं|)
Q8. प्रमेय 6.2 का प्रयोग करते हुए सिद्ध कीजिए की एक त्रिभुज की किन्ही दो भुजाओं के मध्य बिन्दुओं को मिलाने वाली रेखा तीसरी भुजा के समांतर होती है | (याद कीजिए की आप कक्षा IX में ऐसा कर चुके हैं ) |
Proved