Important Questions for CBSE Class 7 Maths Chapter 9

Table of Contents

Rational Numbers Extra Questions Class 7

Also Check: CBSE Class 9 English Grammar

Question 1. Find three rational numbers equivalent to each of the following rational numbers.
(i) \(\frac { -2 }{ 5 }\)
(ii) \(\frac { 3 }{ 7 }\)
Solution:

Question 2. Reduce the following rational numbers in standard form.
(i) \(\frac { 35 }{ -15 }\)
(ii) \(\frac { -36 }{ -216 }\)
Solution:

Question 3. Represent \(\frac { 3 }{ 2 }\) and \(\frac { -3 }{ 4 }\) on number lines.
Solution:

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Question 4. Which of the following rational numbers is greater?
(i) \(\frac { 3 }{ 4 }\), \(\frac { 1 }{ 2 }\)
(ii) \(\frac { -3 }{ 2 }\), \(\frac { -3 }{ 4 }\)
Solution:

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Question 5. Find the sum of

Solution:

Question 6. Subtract:

Solution:

Question 7. Find the product:

Solution:

Also Check: Science Class 9 Chapter 11

Rational Numbers Class 7 Extra Questions Short Answer Type

Question 8. If the product of two rational numbers is \(\frac { -9 }{ 16 }\) and one of them is \(\frac { -4 }{ 15 }\), find the other number.
Solution: Let the required rational number be x.

Question 9. Arrange the following rational numbers in ascending order.

Solution:

Question 10. Insert five rational numbers between:

Solution:

Rational Numbers Class 7 Extra Questions Long Answer Type

Question 11. Evaluate the following:

Solution:

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Question 12. Subtract the sum of \(\frac { -5 }{ 6 }\) and -1\(\frac { 3 }{ 5 }\) from the sum 2\(\frac { 2 }{ 3 }\) and -6\(\frac { 2 }{ 5 }\).
Solution:

Question 13.

Solution:
We have

Question 14. Divide the sum of -2\(\frac { 15 }{ 17 }\) and 3\(\frac { 5 }{ 34 }\) by their difference.
Solution:

Question 15. During a festival sale, the cost of an object is ₹ 870 on which 20% is off. The same object is available at other shops for ₹ 975 with a discount of 6\(\frac { 2 }{ 3 }\) %. Which is a better deal and by how much?
Solution: The cost of the object = ₹ 870
Discount = 20% of ₹ 870 = \(\frac { 20 }{ 100 }\) × 870 = ₹ 174
Selling price = ₹ 870 – ₹ 174 = ₹ 696
The same object is available at other shop = ₹ 975

Selling price = ₹ 975 – ₹ 65 = ₹ 910
Since ₹ 910 > ₹ 696
Hence, deal at first shop is better and by ₹ 910 – ₹ 696 = ₹ 214

Rational Numbers Class 7 Extra Questions Higher Order Thinking Skills (HOTS) Type

Question 16. Simplify:
21.5 ÷ 5 – \(\frac { 1 }{ 5 }\) of (20.5 – 5.5) + 0.5 × 8.5
Solution:
Using BODMAS rule, we have
21.5 ÷ 5 – \(\frac { 1 }{ 5 }\) of (20.5 – 5.5) + 0.5 × 8.5
= 21.5 ÷ 5 – \(\frac { 1 }{ 5 }\) of 15 + 0.5 × 8.5
= 21.5 × \(\frac { 1 }{ 5 }\) – \(\frac { 1 }{ 5 }\) × 15 + 0.5 × 8.5
= 4.3 – 3 + 4.25
= 4.3 + 4.25 – 3
= 8.55 – 3
= 5.55

Question 17. Simplify:

Solution:
Using BODMAS rule, we have
2.3 – [1.89 – {3.6 – (2.7 – 0.77)}] = 2.3 – [1.89 – {3.6 – 1.93}] = 2.3 – [1.89 – 1.67] = 2.3 – 0.22
= 2.08