Rational Numbers Class 7 Extra Questions Maths Chapter 9

# Rational Numbers Class 7 Extra Questions Maths Chapter 9

## Rational Numbers Class 7 Extra Questions Maths Chapter 9

Extra Questions for Class 7 Maths Chapter 9 Rational Numbers

### Rational Numbers Class 7 Extra Questions Very Short Answer Type

Question 1.
Find three rational numbers equivalent to each of the following rational numbers.
(i) $$\frac { -2 }{ 5 }$$
(ii) $$\frac { 3 }{ 7 }$$
Solution: Join Infinity Learn Regular Class Program!

Download FREE PDFs, solved questions, Previous Year Papers, Quizzes, and Puzzles!

+91

Verify OTP Code (required)

I agree to the terms and conditions and privacy policy.

Question 2.
Reduce the following rational numbers in standard form.
(i) $$\frac { 35 }{ -15 }$$
(ii) $$\frac { -36 }{ -216 }$$
Solution: Question 3.
Represent $$\frac { 3 }{ 2 }$$ and $$\frac { -3 }{ 4 }$$ on number lines.
Solution: Question 4.
Which of the following rational numbers is greater?
(i) $$\frac { 3 }{ 4 }$$, $$\frac { 1 }{ 2 }$$
(ii) $$\frac { -3 }{ 2 }$$, $$\frac { -3 }{ 4 }$$
Solution: Question 5.
Find the sum of Solution: Question 6.
Subtract: Solution:  Question 7.
Find the product: Solution: ### Rational Numbers Class 7 Extra Questions Short Answer Type

Question 8.
If the product of two rational numbers is $$\frac { -9 }{ 16 }$$ and one of them is $$\frac { -4 }{ 15 }$$, find the other number.
Solution:
Let the required rational number be x. Question 9.
Arrange the following rational numbers in ascending order. Solution: Question 10.
Insert five rational numbers between: Solution:  ### Rational Numbers Class 7 Extra Questions Long Answer Type

Question 11.
Evaluate the following: Solution:  Question 12.
Subtract the sum of $$\frac { -5 }{ 6 }$$ and -1$$\frac { 3 }{ 5 }$$ from the sum 2$$\frac { 2 }{ 3 }$$ and -6$$\frac { 2 }{ 5 }$$.
Solution: Question 13. Solution:
We have Question 14.
Divide the sum of -2$$\frac { 15 }{ 17 }$$ and 3$$\frac { 5 }{ 34 }$$ by their difference.
Solution: Question 15.
During a festival sale, the cost of an object is ₹ 870 on which 20% is off. The same object is available at other shops for ₹ 975 with a discount of 6$$\frac { 2 }{ 3 }$$ %. Which is a better deal and by how much?
Solution:
The cost of the object = ₹ 870
Discount = 20% of ₹ 870 = $$\frac { 20 }{ 100 }$$ × 870 = ₹ 174
Selling price = ₹ 870 – ₹ 174 = ₹ 696
The same object is available at other shop = ₹ 975 Selling price = ₹ 975 – ₹ 65 = ₹ 910
Since ₹ 910 > ₹ 696
Hence, deal at first shop is better and by ₹ 910 – ₹ 696 = ₹ 214

### Rational Numbers Class 7 Extra Questions Higher Order Thinking Skills (HOTS) Type

Question 16.
Simplify:
21.5 ÷ 5 – $$\frac { 1 }{ 5 }$$ of (20.5 – 5.5) + 0.5 × 8.5
Solution:
Using BODMAS rule, we have
21.5 ÷ 5 – $$\frac { 1 }{ 5 }$$ of (20.5 – 5.5) + 0.5 × 8.5
= 21.5 ÷ 5 – $$\frac { 1 }{ 5 }$$ of 15 + 0.5 × 8.5
= 21.5 × $$\frac { 1 }{ 5 }$$ – $$\frac { 1 }{ 5 }$$ × 15 + 0.5 × 8.5
= 4.3 – 3 + 4.25
= 4.3 + 4.25 – 3
= 8.55 – 3
= 5.55

Question 17.
Simplify: Solution:
Using BODMAS rule, we have
2.3 – [1.89 – {3.6 – (2.7 – 0.77)}] = 2.3 – [1.89 – {3.6 – 1.93}] = 2.3 – [1.89 – 1.67] = 2.3 – 0.22
= 2.08

Question 18. Solution:
Using BODMAS rule, we have  Join Infinity Learn Regular Class Program!

Sign up & Get instant access to FREE PDF's, solved questions, Previous Year Papers, Quizzes and Puzzles!

+91

Verify OTP Code (required)

I agree to the terms and conditions and privacy policy.