Study MaterialsImportant QuestionsKnowing Our Numbers Class 6 Extra Questions Maths Chapter 1

Knowing Our Numbers Class 6 Extra Questions Maths Chapter 1

Knowing Our Numbers Class 6 Extra Questions Maths Chapter 1

Extra Questions for Class 6 Maths Chapter 1 Knowing Our Numbers

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    Knowing Our Numbers Class 6 Extra Questions Very Short Answer Type

    Question 1.
    Write the smallest three digit number whose value does not change on reversing its digits.
    Solution:
    The required number is 101.

    Question 2.
    Write the greatest three digit number which does not change on reversing its digits.
    Solution:
    The required number is 999.

    Question 3.
    What must be added to 203 to get a number whose digits are reversed of the given number?
    Solution:
    The number obtained by reversing the digits of 203 = 302.
    ∴ Difference = 302 – 203 = 99
    Hence, the required number is 99.

    Question 4.
    Write the following in Roman numerals:
    (a) 72
    (b) 38
    Solution:
    (a) 72 = LXXII
    (b) 38 – XXXVIII

    Question 5.
    Write 438 in its expanded form.
    Solution:
    438 = 4 x 100 + 3 x 10 + 8.

    Question 6.
    Write the greatest five-digit number using the digits 4, 2 and 0.
    Solution:
    The greatest five-digit number using the digits 4, 2 and 0 is 44420.

    Question 7.
    The capacity of a water tank is 300 litres. Express its capacity in millilitres.
    Solution:
    We know that
    1 litre = 1000 mL
    ∴ 300 litres = 300 x 1000 mL = 3,00,000 mL
    Hence, the capacity of water tank = 3 lakh millilitres.

    Question 8.
    What is the successor of greatest 6-digit number?
    Solution:
    Greatest 6-digit number = 999999
    Successor of it = 999999 + 1 = 1000000
    i. e., smallest 7-digit number.
    Hence, the required successor = 10,00,000.

    Question 9.
    What is the place value of 7 in 1743?
    Solution:
    Let us write 1743 in its expanded form
    1743 = 1000 + 700 + 40 +3
    Place value of 7 = 700
    Hence, the place value of 7 = 700.

    Knowing Our Numbers Class 6 Extra Questions Short Answer Type

    Question 10.
    Of 7,12,540 and 71,25,400 which number is greater and by how much?
    Solution:
    Since 71,25,400 is a seven-digit number and 7,12,540 is a six-digit number.
    So 71,25,400 is greater than 7,12,540.
    Knowing Our Numbers Class 6 Extra Questions Maths Chapter 1
    Hence 71,25,400 is greater than 7,12,540 by 64,12,860.

    Question 11.
    Write the smallest and the greatest 5-digit numbers using the digits 0,2,4,6,8 (Repetition of digits is not allowed).
    Solution:
    Given digits are 0, 2, 4, 6, 8
    5 – digit greatest number = 86420;
    5 – digit smallest number = 20468.

    Question 12.
    Write the following numbers in ascending order. How many of them are even numbers?
    63,854, 63,584, 65,348, 68,543, 64,835
    Solution:
    The given numbers are 63,854, 63,584, 65,348, 68,543 and 64,835.
    Ascending order is 63,584 ; 63,854 ; 64,835 ; 65,348 ; 68,543
    Even numbers are 63,584, 63,854 and 65,348.

    Question 13.
    Round the given numbers to the nearest tens.
    (a) 48
    (b) 59
    (c) 64
    (d) 215
    Solution:
    Given number Rounded off to tens
    (a) 48 → 50
    (6) 59 → 60
    (c) 64 → 60
    (d) 215 → 220

    Question 14.
    Estimate the following products:
    (а) 86 x 316
    (b) 898 x 786
    Solution:
    (a) 86 x 316
    ∵ 86 → 90 [Rounding off to tens] and 316 → 320 [Rounding off to tens] So, the estimated product is 90 x 320 = 28800

    (b) 898 x 786
    ∵ 898 → 900 [Rounding off to hundreds] and 786 → 800 [Rounding off to hundreds] So, the estimated product is 900 x 800 = 720000.

    Question 15.
    Divide 2,63,175 by 275.
    Solution:
    We have
    Knowing Our Numbers Class 6 Extra Questions Maths Chapter 1
    Hence, quotient = 957 and remainder = 0.

    Question 16.
    A student multiplied 3759 by 231 instead of multiplying by 213. How much was his product greater than the correct product?
    Solution:
    First Method:
    (3759 x 231)-(3759 x 213) = 868329 – 800667 = 67662
    Second Method: 3759 x (231 – 213) = 3759 x 18 = 67662
    Hence, the product difference is 67662.

    Question 17.
    Estimate: 25,148 + 7394 + 9343 + 752
    Solution:
    Estimated values are
    25,148 → 25100
    7394 → 7400
    9343 → 9300
    752 → 800
    So, the estimated sum is 25100 + 7400 + 9300 + 800 = 42600
    Hence, the estimated sum is 42600.

    Question 18.
    Write all the even numbers between 90 and 100 in Roman Numerals.
    Solution:
    Even numbers between 90 and 100, we have 92, 94, 96, 98.
    ∴ 92 = XCII,
    94 = XCIV,
    96 = XCVI,
    98 = XCVIII

    Knowing Our Numbers Class 6 Extra Questions Long Answer Type

    Question 19.
    Write the missing digits in the following sums:
    Knowing Our Numbers Class 6 Extra Questions Maths Chapter 1
    Solution:
    Knowing Our Numbers Class 6 Extra Questions Maths Chapter 1

    Question 20.
    Write Hindu-Arabic numerals for:
    (a) LXXXVI
    (b) LXXV
    (c) XCIX
    (d) XCI
    Solution:
    (a) LXXXVI = 50 + 30 + 6 = 86
    (b) LXXV = 50 + 20 + 5 = 75
    (c) XCIX = (100 – 10) + 9 = 99
    (d) XCI = (100 – 10) + 1 = 91

    Question 21.
    The distance between the school and Reena’s house is 1 km 480 m. Everyday she walks both ways. What distance does she cover in 6 days of a week?
    Solution:
    Distance covered when she walks one way = 1 km 480 m = 1480 m
    Therefore, the distance covered when she walk both ways in a day = 1480 x 2 m = 2960 m
    Total distance covered by Reena in 6 days = 2960 x 6 m = 17760 m or 17 km 760 m.

    Question 22.
    Simplify: 36 ÷ [5 + {4 x 5 ÷ 2}] Solution:
    Given:
    36 ÷ [5 + {4 x 5 ÷ 2}] Using B, O, D, M, A, S
    Knowing Our Numbers Class 6 Extra Questions Maths Chapter 1

    Question 23.
    To stitch a pant 1 m 15 cm cloth is needed. Out of 36 m cloth, how many pants can be stitched and how much cloth will remain?
    Solution:
    Knowing Our Numbers Class 6 Extra Questions Maths Chapter 1
    Cloth required to stitch 1 pant = 1 m 15 cm
    = 100 cm + 15 cm [∵ 1 m = 100 cm] = 115 cm
    Total cloth = 36 m = 36 x 100 cm = 3600 cm
    Therefore number of pants stitched = \(\frac { 3600 }{ 115 }\)
    Hence, 31 pants can be stitched and cloth left over is 35 cm.

    Question 24.
    Write each of the following numbers in figures:
    (a) Eighty-one million four hundred twelve thousand six hundred fifty.
    (b) Twenty million three hundred eighty thousand one hundred.
    (c) Ninety million nine.
    (d) Forty-nine million seven hundred eighty two thousand fifty eight.
    (e) Six millions three hundred fifty-two thousand nine hundred forty-six.
    (f) Seven crore twenty-three lakh eighty-six thousand, five hundred ninety-four.
    (g) Fifty crore forty lakh sixty thousand nine.
    (h) Nineteen crore, ninety lakh, fourteen thousand, six hundred eighty.
    Solution:
    In words In figure
    (а) Eighty-one millions four hundred twelve thousand, six hundred fifty. 81,412,650
    (b) Twenty million three hundred eighty thousand one hundred 20,380,100
    (c) Ninety million nine 90,000,009
    (d) Forty-nine million seven hundred eighty-two thousand fifty-eight 49,782,058
    (e) Six-millions three hundred fifty-two thousand nine hundred forty-six 6,352,946
    (f) Seven crore, twenty-three lakh eighty-six thousand five hundred ninety-four 7,23,86,594
    (g) Fifty crore forty lakh sixty thousand nine 50,40,60,009
    (h) Nineteen crore ninety lakh fourteen thousand six hundred eighty. 19,90,14,680

    Question 25.
    Write True/False for the following statements:
    (a) Roman symbol X cannot be repeated more than three times
    (b) VXXX = 25 …….. .
    (c) Estimate value of274 rounding off to nearest hundreds = 200 …….
    (d) I and X can repeat at the most three times …….
    (e) V, L and D are neither, repeated nor written to the left of greater value symbol ……..
    (f) There are six basic symbols in Roman Numeration system ……..
    Solution:
    (a) True
    (b) False
    (c) False
    (d) True
    (e) True
    (f) False.

    Knowing Our Numbers Class 6 Extra Questions Higher Order Thinking Skills (HOTS)

    Question 26.
    There are two factories located at place P and the other at place Q. From these factories, a certain commodity is to be delivered to each of the depots situated at A, B and C. Weekly production of commodity by P and Q are 120 kg and 150 kg respectively. Weekly requirement of commodity by A, B and C are 80 kg, 90 kg and 100 kg respectively. P delivers 60 kg to A, 40 kg to B and 20 kg to C. How much amount of the commodity should Q deliver to A, B and C to meet their requirement? If the rate of the commodity is ? 20 per kg, find the total amount to be paid to P and Q.
    Solution:
    Knowing Our Numbers Class 6 Extra Questions Maths Chapter 1
    Amount of commodity delivered by P to A = 60 kg
    Amount of commodity delivered by Q to A = 80 – 60 = 20 kg
    Amount of commodity delivered by P to B = 40 kg
    Amount of commodity delivered by Q to B – 90 – 40 = 50 kg
    Amount of commodity delivered by P to C = 20
    Amount of commodity delivered by Q to C = 100 – 20 = 80 kg.
    Now Amount of money to be paid to P by A, B and C = ₹( 60 x 20 + 40 x 20 + 20 x 20)
    = ₹ (1200 + 800 + 400)
    = ₹ 2400
    and amount of money to be paid to Q by A, B and C
    = ₹ (20 x 20 + 50 x 20 + 80 x 20)
    = ₹ (400 + 1000 + 1600) = ₹ 3000
    Hence, the total amount
    = ₹ 2400 + ₹ 3000 = ₹ 5400.

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