Young’s double slit experiment is made in a liquid. The 10th bright fringe in liquid lies where 6th dark fringe lies in vacuum. The refractive index of the liquid is approximately
A concave mirror of short aperture and radius of curvature 10cm is cut into two equal parts, slightly separated and placed in front of a monochromatic line source S of wavelength 2000 A ° as shown in figure. Consider only interference in reflected light after first reflection from mirrors. Assume direct light from S is blocked from reaching the screen. If half of reflecting surface of upper part of mirror is painted black then choose correct option:
In YDSE, find the thickness (in μm ) of a glass slab ( μ = 1 .5 ) which should be placed before the upper slit S 1 so that the central maximum now lies at a point where 5th bright fringe was lying earlier (before inserting the slab). Wavelength of light used is 5000 Å .
Interference fringes were produced in Young’s double-slit experiment using light of wavelength 5000 Å . When a film of thickness 2.5 × 10 -3 cm was placed in front of one of the slits, the fringe pattern shifted by a distance equal to 20 fringe-width. The refractive index of the material of the film is
In a Young’s double slit experiment d = 1 m m , λ = 6000 A 0 and D = 1 m (where d, λ and D have usual meaning). Each of slit individually produces the same intensity on the screen. Then select the correct option(s).
Two plane mirrors, a source S of light, emitting monochromatic rays of wavelength λ and a screen are arranged as shown in figure. If angle θ is very small, the fringe width of interference pattern formed on screen by reflected rays is:
In a YDSE experiment, the two slits are covered with a transparent membrane of negligible thickness which allows light to pass through it but does not allow water. A glass slab of thickness t = 0.41 mm and refractive index μ g = 1.5 is placed in front of one of the slits as shown in the figure. The separation between the slits is d = 0.30 mm. The entire space to the left of the slits is filled with water of refractive index μ w = 4 / 3 .A coherent light of intensity I and absolute wavelength λ = 5000 A o is being incident on the slits making an angle 30º with horizontal. If screen is placed at a distance D =1m from the slits, then the distance of central maxima from O is n × 0.83 cm. Then the value of n is
In a Young’s double slit experiment d = 1 m m , λ = 6000 A 0 and D = 1 m (where d, λ and D have usual meaning). Each of slit individually produces the same intensity on the screen. Then select the correct option(s).
A thin large film having refractive index μ = 3 2 , is placed in front of slits S 1 and S 2 of Young’s double slit experiment such that its thickness varies according to the equation t = t 0 cos 2 5 π y 4 d where y = 0 is taken at S 1 . Find the value of t 0 such that there is central maxima at P (refer diagram) A s s u m e D > > d
Two slits s1 and s2 are on a plane inclined at an angle of 45 0 with horizontal. The distance between the slits is 2 mm. A monochromatic point source S of wavelength λ = 5000 A 0 is placed at a distance 1 / 2 mm from the midpoint of slits as shown in figure. The screen is placed at a distance of 2 m. The fringe width of interference pattern on the screen is n 10 m m . Find the integer closest to n
In a calm pond, water μ = 4 / 3 is filled uniformly upto 1 m depth. The maximum wavelength of the electromagnetic radiation indication incident normally from air onto the water surface, that will be strongly reflected is: [assume: n ground > n water ]
Two slits are separated by 0.3 mm. A beam of 500 nm light strikes the slits producing an interference pattern. The number of maximas observed in the angular range − 30 ° < θ < 30 ° are 590 + p . Calculate p = ?
A parallel beam of light strikes a piece of transparent glass having cross section as shown in the figure below. Correct shape of the emergent wavefront will be (figures are schematic and not drawn to scale)-
Two point monochromatic and coherent sources of light of wavelength λ are placed on the dotted line in front of an infinite screen. The source emit waves in phase with each other. The distance between S 1 and S 2 is d while their distance from the screen is much larger. Then
A concave mirror of short aperture and radius of curvature 10cm is cut into two equal parts, slightly separated and placed in front of a monochromatic line source S of wavelength 2000 A ° as shown in figure. Consider only interference in reflected light after first reflection from mirrors. Assume direct light from S is blocked from reaching the screen. Assume A is the position of first order maxima on the screen. Now the point object is moved away from mirror normal to screen with constant speed, then:
A concave mirror of short aperture and radius of curvature 10cm is cut into two equal parts, slightly separated and placed in front of a monochromatic line source S of wavelength 2000 A ° as shown in figure. Consider only interference in reflected light after first reflection from mirrors. Assume direct light from S is blocked from reaching the screen. Assume A is the position of first order maxima on the screen. Now the point object is moved away from mirror normal to screen with constant speed, then:
Two waves from coherent sources meet at a point in a path difference of ∆ x . Both the waves have same intensities I 0 . Match the following two columns. Column I Column II (a) If Δx = λ / 3 (p) Resultant intensity will become three times of I 0 (b) If Δx = λ / 6 (q) Resultant intensity will remain same as that of I 0 (c) If Δx = λ / 4 (r) Resultant intensity will become two times of I 0 (d) If Δx = λ / 2 (s) Resultant intensity will become zero
The maximum intensity in Young’s double slit experiment is I 0 . Distance between the slits is d = 5 λ , where λ is the wavelength of monochromatic light used in the experiment. The intensity of light in front of one of the slits on a screen at a distance D = 10d is
In Young’s double-slit experiment, an interference pattern is obtained on a screen by a light of wavelength 6000 Å , coming from the coherent sources S 1 and S 2 . At certain point P on the screen third dark fringe is formed. Then the path difference S 1 P – S 2 P in microns is
In YDSE, the source is placed symmetrical to the slits. If a transparent slab is placed in front of the upper slit, then (slab can absorb a fraction of light)
