Table of Contents
BODMAS Rule Questions for Class 10
The BODMAS rule is important in math as it helps us solve arithmetic expressions accurately. It stands for Brackets, Order (powers and roots), Division, Multiplication, Addition, and Subtraction. This rule guides the sequence of operations in an expression, ensuring we get the right answers consistently. Knowing BODMAS is crucial for Class 10 students to handle tough math problems effectively. First, tackle what’s inside brackets. Then, deal with powers or roots. Next, move on to division and multiplication, working from left to right. Finally, wrap up with addition and subtraction, also from left to right. This method ensures you solve math expressions correctly every time
BODMASS – Introduction
BODMAS, stands for Brackets, Orders, Division, Multiplication, Addition, and Subtraction, serves as a fundamental rule of mathematics. It helps us know which operations to do first, making our calculations consistent and accurate.
B: Brackets (solve expressions inside parentheses, square brackets, curly braces, etc.)
O: Order (solve powers and roots)
D: Division
M: Multiplication
A: Addition
S: Subtraction
Let’s consider the expression
10+(5×3+2)
Let’s apply BODMAS to simplify this expression step by step:
First, solve what’s inside the brackets:
5×3=15
Now, add 2:
15+2=17
Finally, add 10:
10+17=27
So, using BODMAS, the expression simplifies to
27.
BODMAS Questions for Class 10 with Answers
Here are some interesting BODMAS questions for class 10 with solutions and topics of BODMAS. One can download BODMAS Questions with answers pdf and solve those questions to increase their calculation in exams.
Question 1: Simplify the expression 15−[3×(4+2)−5]
Solution:
Begin by adding the terms inside the parentheses: 4+2=6.
Multiply the result by 3: 3×6=18.
Subtract 5 from this value: 18−5=13.
Finally, subtract the obtained result from 15: 15−13=2.
Answer: The simplified expression is 2
Question 2: Evaluate 20÷{2×(3×2)+4}.
Solution:
First, perform the operation within the innermost parentheses: 3×2=6.
Multiply the result by 2: 2×6=12.
Add 4 to this value: 12+4=16.
Then, divide 20 by the obtained result: 20÷16=1.25.
Answer: The simplified expression is 1.25
Question 3: Simplify 25+{4×[8−(2×3)]}.
Solution:
Start by calculating the expression within the inner parentheses: 2×3=6.
Subtract this result from 8: 8−6=2.
Next, multiply 4 by the obtained value: 4×2=8.
Then, add 25 to this result: 25+8=33.
Answer: The simplified expression is 33
Question 4: Find the value of 18−{6+[4×(5−2)]}.
Solution:
Begin by evaluating the expression inside the square brackets: 5−2=3.
Multiply this result by 4: 4×3=12.
Then, add 6 to the obtained value: 6+12=18.
Finally, subtract this result from 18: 18−18=0.
Answer: The simplified expression is 0
Question 5: Simplify 36÷{4+[5×(3−1)]}.
Solution:
First, calculate the expression within the inner parentheses: 3−1=2.
Multiply this result by 5: 5×2=10.
Then, add 4 to the obtained value: 4+10=14.
Finally, divide 36 by the result: 36÷14≈2.571.
Answer: The simplified expression is approximately 2.571
Question 6: Evaluate 30−{7×[6−(2×2)]}.
Solution:
Start by calculating the expression inside the inner parentheses: 2×2=4.
Subtract this result from 6: 6−4=2.
Next, multiply 7 by the obtained value: 7×2=14.
Then, subtract this result from 30: 30−14=16.
Answer: The simplified expression is 16.
Some Tricky BODMAS Questions for Class 10
Solve these Difficult BODMAS Questions and improve your mathematical skills.
1. Expression: 8÷8 of 8+88÷8×8+88÷8 of 8+88÷8×8+88÷8 of 8+88÷8×8+88÷8 of 8+88÷8×8+8
Solution
- Order of Operations (PEMDAS/BODMAS): We follow the order of operations to simplify the expression.
- Simplify Inside Parentheses: There are no parentheses in this expression.
- Perform Multiplication and Division from left to right: 8÷8 of 8+88÷8×8+88÷8 of 8+88÷8×8+88÷8 of 8+88÷8×8+88÷8 of 8+88÷8×8+8
=1 of 8+11×8+11 of 8+11×8+8=1 of 8+11×8+11 of 8+11×8+8
Here, 8÷88÷8 simplifies to 11. - Perform Remaining Multiplication and Division from left to right: 1 of 8+11×8+11 of 8+11×8+81 of 8+11×8+11 of 8+11×8+8
=1 of 8+88+11 of 8+88+8=1 of 8+88+11 of 8+88+8
Now, we have 1111 multiplied by 88 which gives us 8888. - Addition and Subtraction from left to right: 1 of 8+88+11 of 8+88+81 of 8+88+11 of 8+88+8
=8+88+88+88+8=8+88+88+88+8
Now, we perform the operation: 11 of 88 which results in 88. - Final Addition: 8+88+88+88+88+88+88+88+8
=8+88+88+88+8=8+88+88+88+8
=280
So, the expression simplifies to 280
2. Expression: 18–[6–{4–(8–6+3)}]18–[6–{4–(8–6+3)}]
=18−[6−{4−(5)}]=18−[6−{4−(5)}]
=18−[6−{−1}]=18−[6−{−1}]
=18−[6+1]=18−[6+1]
=18−7=18−7
Answer: 1111
Now Attempt these Questions and Check your Performance
- 1. Evaluate: 8 ÷ 4 × (6 + 2 of 4) + 32 – 2
- 2. Evaluate: 0.34 ÷ 1.7 + 45 × 2
- 3. Evaluate: [{(45 + 90 ÷ 3 × 6) × 2} ÷ ½ ] × 56
- 4. Evaluate: ⅖ + ¾ × ⅘ ÷ 6/5.
- 5. Evaluate: 45 + 34 ÷ 2 × 82 ÷ 16 × ( – 3).
FAQs on BODMAS Questions for Class 10
What is the BODMAS rule for Class 10?
The BODMAS rule for Class 10 refers to the order of operations in mathematics, which dictates that calculations should be performed in the following sequence: Brackets, Orders (exponents and roots), Division and Multiplication (from left to right), and Addition and Subtraction (from left to right).
Who is the father of BODMAS?
The concept of BODMAS, or the order of operations, was not introduced by a single individual. It is a mathematical convention followed worldwide.
What does the O in BODMAS stand for?
The O in BODMAS stands for Of.
How is the BODMAS rule used in real life?
The BODMAS rule is used in real life to simplify mathematical expressions and ensure that calculations are performed accurately and consistently. It helps in solving various problems in fields such as finance, engineering, and science by providing a standardized method for carrying out calculations.
Does BODMAS apply without brackets?
Yes, BODMAS applies even when there are no brackets present. The rule dictates the order in which mathematical operations should be performed, starting with any brackets present, followed by exponents, then multiplication and division, and finally addition and subtraction.
