ChemistryThe number of oxygen molecules present in 100 grams of limestone is

The number of oxygen molecules present in 100 grams of limestone is

A
$4 N_{0}$
B
$3 N_{o}$
C
$1.5 N_{o}$
D
$N_{0}$

Solution:

The molecular formula of limestone is $C a C O_{3}$

100grams of limestone = 1 mole = $N_{A}$ molecules.

Limestone contains 3 mole atom of oxygen = 3 $N_{A}$ atoms.

2 atoms of oxygen = 1 molecule of $O_{2}$

3 atoms of oxygen = 1.5 molecule of $O_{2}$

Hence the correct option is (C).

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